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fix absolute value of coupling constant
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1 changed files with 3 additions and 3 deletions
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@ -482,13 +482,13 @@ constant. With these considerations in mind we can simplify
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\cref{eq:32} to
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\cref{eq:32} to
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\begin{equation}
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\begin{equation}
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\label{eq:64}
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\label{eq:64}
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η_{m}=κ\frac{πn_{B}}{c}∑_{σ=\pm,β,β'}U_{βm}U^\ast_{β'm}δ_{\sgn(β),σ} δ_{\sgn(β'),σ}
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η_{m}=\abs{κ}\frac{πn_{B}}{c}∑_{σ=\pm,β,β'}U_{βm}U^\ast_{β'm}δ_{\sgn(β),σ} δ_{\sgn(β'),σ}
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\end{equation}
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\end{equation}
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and
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and
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\begin{gather}
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\begin{gather}
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\label{eq:34}
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\label{eq:34}
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\dot{d}_{γ} =
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\dot{d}_{γ} =
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-\iu\bqty{\pqty{ω_{γ}-\iu \tilde{η}_{γ}}d_{γ} + \sqrt{κ} ∑_{σ=\pm}
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-\iu\bqty{\pqty{ω_{γ}-\iu \tilde{η}_{γ}}d_{γ} + \sqrt{κ^\ast} ∑_{σ=\pm}
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U^{σ}_{γ}(t) \frac{b_{\inputf}(t)}{\sqrt{ω_{0}}}}\\
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U^{σ}_{γ}(t) \frac{b_{\inputf}(t)}{\sqrt{ω_{0}}}}\\
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U^{σ}_{γ}(t) = ∑_{m,β} δ_{\sgn({β}),σ}U^\ast_{βm}\pqty{O^{-1}(t)}_{γm} \eu^{\iu ω_{m}^{0}t}= ∑_{m,β} δ_{\sgn({β}),σ}U^\ast_{βm}\pqty{O^{-1}}_{γm}\eu^{\iu (ω_{m}^{0}-ε_{m})t}.
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U^{σ}_{γ}(t) = ∑_{m,β} δ_{\sgn({β}),σ}U^\ast_{βm}\pqty{O^{-1}(t)}_{γm} \eu^{\iu ω_{m}^{0}t}= ∑_{m,β} δ_{\sgn({β}),σ}U^\ast_{βm}\pqty{O^{-1}}_{γm}\eu^{\iu (ω_{m}^{0}-ε_{m})t}.
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\end{gather}
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\end{gather}
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@ -506,7 +506,7 @@ We can now proceed to integrate \cref{eq:34} to obtain
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with
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with
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\begin{equation}
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\begin{equation}
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\label{eq:37}
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\label{eq:37}
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χ_{γ}(t) = κ \eu^{-\pqty{\iu ω_{γ} + \tilde{η}_{γ}}t}.
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χ_{γ}(t) = \abs{κ} \eu^{-\pqty{\iu ω_{γ} + \tilde{η}_{γ}}t}.
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\end{equation}
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\end{equation}
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When constructing the total output field, we have to remember how the
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When constructing the total output field, we have to remember how the
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