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throug with flow
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src/flow.tex
94
src/flow.tex
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@ -349,7 +349,7 @@ The system state is then recovered through
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The usual step is now to insert \(\id =D(\vb{y})D^†(\vb{y})\) and
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The usual step is now to insert \(\id =D(\vb{y})D^†(\vb{y})\) and
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permute one \(D\) operator to the rightmost side in
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permute one \(D\) operator to the rightmost side in
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\cref{eq:shiftbath_system} when tracing out the bath to arrive at a
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\cref{eq:shiftbath_system} when tracing out the bath to arrive at a
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new time evolution operator
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new time evolution operator~\cite{RichardDiss,Strunz2001Habil}
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\begin{equation}
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\begin{equation}
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\label{eq:utilde}
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\label{eq:utilde}
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\tilde{U}(t) = D^†(\vb{y})U(t)D(\vb{y})
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\tilde{U}(t) = D^†(\vb{y})U(t)D(\vb{y})
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@ -457,7 +457,15 @@ in \cref{sec:hopsvsanalyt} that consistent results can be obtained
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using the derivative of the stochastic process \(ξ\), which avoids the
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using the derivative of the stochastic process \(ξ\), which avoids the
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numeric time derivative in \cref{eq:gettingarounddot}. This time
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numeric time derivative in \cref{eq:gettingarounddot}. This time
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derivative can however be performed after the ensemble mean on a
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derivative can however be performed after the ensemble mean on a
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function that is generally smooth, even for non-differentiable \(ξ\).
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function that is generally smooth, even for non-differentiable
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\(ξ\). However, this entails storing the state in a very high
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temporal resolution or interpolating with a suitable ansatz.
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We now have a very capable method at hand, that can already be
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efficiently applied in quite general settings. However, systems with
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multiple heat baths of different temperature still remain to be
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discussed in \cref{sec:multibath}.
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\section{Generalization to Multiple Baths}
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\section{Generalization to Multiple Baths}
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\label{sec:multibath}
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\label{sec:multibath}
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@ -478,10 +486,8 @@ arbitrary operators acting on the system Hilbert space.
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Note that this models a situation where each bath couples with the
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Note that this models a situation where each bath couples with the
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system through exactly one spectral density and is therefore not fully
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system through exactly one spectral density and is therefore not fully
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general.
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general. We refer to \cref{sec:hops_multibath} for an review of the
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NMQSD theory and HOPS method for multiple baths.
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We refer to \cref{sec:hops_multibath} for an review of the NMQSD
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theory and HOPS method for multiple baths.
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Because the bath energy change is being calculated directly and not
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Because the bath energy change is being calculated directly and not
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through energy conservation as in~\cite{Kato2016Dec}, we find
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through energy conservation as in~\cite{Kato2016Dec}, we find
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@ -519,6 +525,11 @@ states more readily than single bath hierarchy states as the
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correlations between the baths are expected to be
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correlations between the baths are expected to be
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small~\cite{Zhang2018Apr}.
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small~\cite{Zhang2018Apr}.
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Now that we have discussed the multi-bath case, the last ingredient we
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are lacking for thermodynamical applications is the ability to handle
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time dependent Hamiltonians. However, this will pose no great
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challenge as we will find out in \cref{sec:timedep}.
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\section{Generalization to Time Dependent Hamiltonians}
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\section{Generalization to Time Dependent Hamiltonians}
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\label{sec:timedep}
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\label{sec:timedep}
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To extract energy from a quantum thermal machine without an explicit
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To extract energy from a quantum thermal machine without an explicit
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@ -538,17 +549,21 @@ For the total power we find
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which can be evaluated as we will find in \cref{sec:intener} by
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which can be evaluated as we will find in \cref{sec:intener} by
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replacing \(L(t)\) with \(\dot{L}(t)\) in \cref{eq:interhops}.
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replacing \(L(t)\) with \(\dot{L}(t)\) in \cref{eq:interhops}.
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The bath energy flow can now be computed for the most general model
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\cref{eq:generalmodel} that the NMQSD introduced in
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\cref{sec:nmqsd_basics} can handle. Finally, we depart from the
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concrete observable of the bath energy flow \cref{eq:heatflowdef} and
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introduce a more general class in \cref{sec:general_obs}.
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\section{General Collective Bath Observables}
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\section{General Collective Bath Observables}
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\label{sec:general_obs}
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\label{sec:general_obs}
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Now that we have introduced the formalism using the example of the
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Now that we have introduced the formalism using the example of the
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bath energy flow \(J\) in
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bath energy flow \(J\) in
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\cref{sec:flow_lin,sec:nonlin_flow,sec:lin_finite,sec:multibath,sec:timedep},
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\cref{sec:flow_lin,sec:nonlin_flow,sec:lin_finite,sec:multibath,sec:timedep},
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we may proceed to more general observables of the form can be
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we may proceed to more general observables of the form
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generalized to calculate expectation values (and thus moments) of
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arbitrary observables of the form
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\begin{equation}
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\begin{equation}
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\label{eq:collective_obs}
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\label{eq:collective_obs}
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O = f(B^†, B) = ∑_{α}F_α\qty(B^†)^{α_1}B^{α_2}
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O = f(B^†, B) = ∑_{α}F_α\otimes \qty(B^†)^{α_1}B^{α_2}
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\end{equation}
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\end{equation}
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where \(α\) is a two-dimensional multi-index, \(B\) is as
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where \(α\) is a two-dimensional multi-index, \(B\) is as
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in~\cref{eq:totalH} and the \(F_α\) are general observables acting on
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in~\cref{eq:totalH} and the \(F_α\) are general observables acting on
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@ -568,11 +583,11 @@ interaction picture with respect to \(H_{\bath}\).
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For zero temperature, we find following the procedures of
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For zero temperature, we find following the procedures of
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\cref{sec:flow_lin},
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\cref{sec:flow_lin},
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\begin{align}
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\begin{align}
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\label{eq:bmel}\mel{z}{B^b}{ψ} &= (-\iu D_t)^b\ket{ψ(η^\ast,t)}
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\label{eq:bmel}\mel{z}{B^b(t)}{ψ} &= (-\iu D_t)^b\ket{ψ(η^\ast,t)}
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= (-\iu)^b
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= (-\iu)^b
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∑_{\abs{\vb{k}}=b}\binom{b}{\vb{k}} \iu^{\vb{k}}
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∑_{\abs{\vb{k}}=b}\binom{b}{\vb{k}} \iu^{\vb{k}}
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\sqrt{\frac{G^{\vb{k}}}{\vb{k}!}}ψ^{\vb{k}}\\
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\sqrt{\frac{G^{\vb{k}}}{\vb{k}!}}ψ^{\vb{k}}\\
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\label{eq:bdagmel}\mel{ψ}{\qty(B^†)^a}{z} &=
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\label{eq:bdagmel}\mel{ψ}{\qty(B^†(t))^a}{z} &=
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\begin{aligned}[t]
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\begin{aligned}[t]
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\qty(\mel{z}{B^a}{ψ})^†&= \qty((-\iu D_t)^a\ket{ψ(η^\ast,t)})^\dag\\
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\qty(\mel{z}{B^a}{ψ})^†&= \qty((-\iu D_t)^a\ket{ψ(η^\ast,t)})^\dag\\
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&= (\iu)^a∑_{\abs{\vb{k}}=a}\binom{a}{\vb{k}} (-\iu)^{\vb{k}}
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&= (\iu)^a∑_{\abs{\vb{k}}=a}\binom{a}{\vb{k}} (-\iu)^{\vb{k}}
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@ -581,7 +596,7 @@ For zero temperature, we find following the procedures of
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\end{align}
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\end{align}
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where \(\vb{k}! = k_1!k_2!\ldots\) and
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where \(\vb{k}! = k_1!k_2!\ldots\) and
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\(G^{\vb{k}}=G_1^{k_1}G_2^{k_2}\ldots\) following the usual
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\(G^{\vb{k}}=G_1^{k_1}G_2^{k_2}\ldots\) following the usual
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conventions of multi-indices. Thus, expressions involving the bath
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conventions for multi-indices. Thus, expressions involving the bath
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operator \(B\) to the \(b\)th power lead to expressions involving the
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operator \(B\) to the \(b\)th power lead to expressions involving the
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hierarchy states of depth \(b\). The truncation of the hierarchy
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hierarchy states of depth \(b\). The truncation of the hierarchy
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corresponds to neglecting the expectation value of all powers of \(B\)
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corresponds to neglecting the expectation value of all powers of \(B\)
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@ -608,8 +623,8 @@ which may be substituted into the above.
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The nonlinear method can be accommodated as in
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The nonlinear method can be accommodated as in
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\cref{sec:nonlin_flow}. For the expressions like~\cref{eq:f_ex_zero}
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\cref{sec:nonlin_flow}. For the expressions like~\cref{eq:f_ex_zero}
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involving the HOPS hierarchy states this reduces to dividing by the
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involving the HOPS hierarchy states the method can be implemented by
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norm of the zeroth hierarchy state.
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dividing by the squared norm of the zeroth hierarchy state.
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The generalization to multiple baths may be performed in the same
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The generalization to multiple baths may be performed in the same
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manner as was discussed in \cref{sec:multibath}. This allows to
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manner as was discussed in \cref{sec:multibath}. This allows to
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@ -628,15 +643,15 @@ and inserting the coherent state resolution of unity we find terms of
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the form
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the form
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\begin{equation}
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\begin{equation}
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\label{eq:with_process}
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\label{eq:with_process}
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\mel{z}{\qty(B^\dag)^b}{ψ} \sim \qty(η^\ast_{t})^b\ket{ψ(η^\ast,t)}.
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\mel{z}{\qty(B^\dag(t))^b}{ψ} \sim \qty(η^\ast_{t})^b\ket{ψ(η^\ast,t)}.
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\end{equation}
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\end{equation}
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The corresponding version of~\cref{eq:f_ex_zero} would only depend on
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The corresponding version of~\cref{eq:f_ex_zero} would only explicitly
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the zeroth order state and the stochastic processes. It has been
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depend on the zeroth order state and the stochastic processes. It has
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observed that expressions involving the stochastic process directly
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been observed that expressions involving the stochastic process
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tend to converge slower. However, this statement comes without
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directly tend to converge slower. However, this statement comes
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empirical proof and its verification may be left to future study. An
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without empirical proof and its verification may be left to future
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explanation may be that the first hierarchy states fluctuate about
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study. An explanation may be that the first hierarchy states fluctuate
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their average dynamics whereas the stochastic process fluctuates
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about their average dynamics whereas the stochastic process fluctuates
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around zero and does not contain much information about the actual
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around zero and does not contain much information about the actual
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dynamics.
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dynamics.
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@ -652,10 +667,10 @@ dynamics.
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% \end{cases}
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% \end{cases}
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% \end{equation}
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% \end{equation}
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% so that we end up with a process that is some approximation of white noise.
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% so that we end up with a process that is some approximation of white noise.
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Also, this alternative method could be used convergence and
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Also, this alternative method could be used as a convergence and
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consistency check, as expressions of the form~\cref{eq:with_process}
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consistency check, as expressions of the form~\cref{eq:with_process}
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only involve the hierarchy cutoff and the exponential expansion of the
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involve the hierarchy cutoff and the exponential expansion of the BCF
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BCF in an indirect manner.
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only in an indirect manner.
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\subsection{Interaction Energy}
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\subsection{Interaction Energy}
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\label{sec:intener}
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\label{sec:intener}
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@ -665,19 +680,17 @@ calculate the expectation value of the interaction energy
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energy is also an effective way to quantify the interaction strength.
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energy is also an effective way to quantify the interaction strength.
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For zero temperature and the nonlinear method we arrive at
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For zero temperature and the linear method we arrive at
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\begin{equation}
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\begin{equation}
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\label{eq:intexp}
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\label{eq:intexp}
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\ev{H_\inter} =
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\ev{H_\inter} =
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-\i
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-\i
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\mathcal{M}_{\tilde{η}^\ast}\frac{\mel{\psi(\tilde{η},t)}{L^†\tilde{D}_t}{\psi(\tilde{η}^\ast,t)}}{\braket{\psi(\tilde{η},t)}{\psi(\tilde{η}^\ast,t)}}
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\mathcal{M}_{{η}^\ast}{\mel{\psi({η},t)}{L^†D_t}{\psi({η}^\ast,t)}}
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+ \cc.
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+ \cc.
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\end{equation}
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\end{equation}
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This is a application of the formalism discussed
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This is a application of the formalism discussed
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in~\cref{sec:general_obs}.
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in~\cref{sec:general_obs}. The expression for the nonlinear method is
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obtained simply by normalizing the above expression.
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The expression for the linear method is obtained by
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simply leaving out the normalization.
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In HOPS terms \cref{eq:intexp} corresponds to
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In HOPS terms \cref{eq:intexp} corresponds to
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\begin{equation}
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\begin{equation}
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@ -698,17 +711,16 @@ stochastic process.
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\subsection{Higher Orders of the Coupling Hamiltonian}
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\subsection{Higher Orders of the Coupling Hamiltonian}
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\label{sec:higher_order_coupling}
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\label{sec:higher_order_coupling}
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In this section, the question of how many hierarchy orders have to be
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In this section, we address the question of how many hierarchy orders
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included in the simulation to consistently calculate the expectation
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have to be included in the simulation to consistently calculate the
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value of powers of the interaction Hamiltonian. Being nonessential for
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expectation value of powers of the interaction Hamiltonian. Being
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the understanding of the rest of the work, this section may be
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nonessential for the understanding of the rest of the work, this
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skipped.
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section may be skipped.
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For self adjoint coupling operators \(L=L^\dag\) we can use Wick's
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For self adjoint coupling operators \(L=L^\dag\) we can use Wick's
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theorem to find a normally ordered expression for \(H_\inter^n=L^n(B^\dag +
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theorem to find a normally ordered expression for
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B)^n\).
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\(H_\inter^n=L^n(B^\dag + B)^n\). The relevant contraction of
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\((B^\dag + B)(B^\dag + B)\) is
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The relevant contraction of \((B^\dag + B)(B^\dag + B)\) is
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\begin{equation}
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\begin{equation}
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\label{eq:contraction_b}
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\label{eq:contraction_b}
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(B^\dag + B)(B^\dag + B) - \mathopen{:} (B^\dag + B)(B^\dag + B)\mathclose{:} = α(0)
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(B^\dag + B)(B^\dag + B) - \mathopen{:} (B^\dag + B)(B^\dag + B)\mathclose{:} = α(0)
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