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Remove jupyter-io-lambda, jupyter-subscriber

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Nathaniel Nicandro 2020-05-12 07:04:41 -05:00
parent 3af33b7736
commit 9800626d8e
1 changed files with 0 additions and 23 deletions
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23
jupyter-monads.el
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@ -150,29 +150,6 @@ context."
;; when called, takes you into the event monad. The lambda being
;; returned represents the lifting of an IO value into the event
;; monad.
;;
;; TODO: Ensure that spec has the right form
;; Sendable and subscribable
(defmacro jupyter-subscriber (spec &rest cases)
(declare (indent 1))
;; Since a subscriber cannot be subscribed to, it is just a function
;; that handles events other than 'subscribe.
;;
;; NOTE: A subscriber ignores events it cannot handle.
`(lambda (&rest ,args)
(cl-destructuring-bind ,spec (cdr ,args)
(pcase (car ,args)
('subscribe (error "Cannot subscribe to a subscriber"))
,@cases))))
(defmacro jupyter-io-lambda (spec &rest cases)
(declare (indent 1))
`(lambda (&rest ,args)
(cl-destructuring-bind ,spec (cdr ,args)
(pcase (car ,args)
,@cases
(_ (error "Unhandled I/O: %s" args))))))
(defun jupyter-publish-to-subscribers (subs args)
(delq nil
(mapcar