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fix blunder
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@ -222,7 +222,7 @@ result can also be expressed in terms of the pseudo-rapidity
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\langle\abs{\mathcal{M}}^2\rangle &= p^4\cdot\mathfrak{F}\cdot
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32\cdot\qty[\frac{(1-c)(1+c)}{s'^4}] + \qty[\frac{(1-c)(1+c)}{c'^4}] \\
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&= \frac{4}{3}(gZ)^4 \cdot\frac{1+\cos^2(\theta)}{\sin^2(\theta)} =
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\frac{4}{3}(gZ)^4\cdot(2\cosh(\eta) - 1)
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\frac{4}{3}(gZ)^4\cdot(\tanh(\eta)^2 + 1)
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\end{split}
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\end{equation}
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%
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