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Merge branch 'master' of https://github.com/henrydatei/TUD_MATH_BA
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@ -43,7 +43,7 @@ Sei $G$ eine Gruppe, $g\in G$.
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\item $m=\infty\Rightarrow\ord(g)=\infty$: klar
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\item $m<\infty\Rightarrow\langle g\rangle=\{g^k\mid 0\le k<m\}$: Für $k\in\whole$ schreibe $k=qm+r$ mit $q,r\in\whole$ und $0\le r<m$
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\begin{align}
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g^k=g^{qm+r}=(\underbrace{g^m}_{=1})^q\cdot g^r=g^r\in{^1,g,...,g^{m-1}}\notag
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g^k=g^{qm+r}=(\underbrace{g^m}_{=1})^q\cdot g^r=g^r\in\{1,g,...,g^{m-1}\}\notag
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\end{align}
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\end{itemize}
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\end{proof}
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